Could Cinderella’s Glass Slippers Physically Exist Without Shattering?

Could Cinderella’s Glass Slippers Physically Exist Without Shattering?

It is delightful to have my masters degree in Mechanical Engineering put to use in resolving age old engineering problems.

One can never know the exact shape or size of the slippers that Cinderella wore, but one can hazard a guess that they must have looked something like:

Could Cinderella’s Glass Slippers Physically Exist Without Shattering?

Now, let’s talk about failure. No, not about Cinderella’s failure to keep her shoes on her feet, but about mechanical failure. Whenever we design something that needs to bear force, we test for various possible modes of failure and try to ensure that our object is strong against all of them.

Now, one possible way the slippers could break is by yielding to the compressive stress arising due to Cinderella’s weight. But will that happen?

We can safely assume that Cindy didn’t weigh more than than 50 kgs. I mean, her cousins were fat and ugly, so we have to leave them some room on the top, right? Let’s assume this weight to be applied uniformly across the shoe. Note that, as Yehong Zhu pointed out in a comment, the toe region of a heeled shoe bears almost thrice as much force as the heel region, but it won’t matter for our purposes.

Could Cinderella’s Glass Slippers Physically Exist Without Shattering?

Using a rough estimate of her foot size, her foot area comes out to be about

Could Cinderella’s Glass Slippers Physically Exist Without Shattering?

If 50 kgs of weight were to be applied uniformly across this area, the compressive stress developed in the material would be :

Could Cinderella’s Glass Slippers Physically Exist Without Shattering?

The Yield strength of ordinary glass for compressive stress is approximately 50 MPa, which is 3 orders of magnitude more than what Cinderella’s weight can produce, so we can safely conclude that any regular glass can sustain it. Since the stress is so low, we don’t even need to worry about the uneven loading on the shoe.

So, is she safe now? Can she safely dance at the ball without fear of tiny shards of glass cutting her skin and ruining her dress?

Not so soon, buddy!

There’s another way her shoe could break, and this is due to the compressive stress due to the bending moment applied to her heel every time she walks.

Now, I don’t want to be here all day, and I don’t want to model her shoe in ANSYS, so I will make a few simplifying assumptions. Let her heel have a diameter 2 centimetres. and have a length of 6 centimetres from the tip to the point where it joins the rest of the shoe. The heel can now be modelled as a simple cantilever beam of circular cross section.

Could Cinderella’s Glass Slippers Physically Exist Without Shattering?

I’m in a bit of a hurry and I have to get back to reading The Casual Vacancy (2012 book), so I will defer to this
for the actual calculation of the maximum bending stress. I will assume her stepping angle to be about 30°, which means that only half of her weight (500sin 30) would act in the normal direction to the heel (causing the bending). Plugging 250N as the bending force and the rest of the figures in place, we get the maximum bending stress in the heel to be 19 MPa. Note that this is dangerously close to our critical stress of . Even if we make a few more allowances by making the heel thicker or the stepping angle smaller, we cannot let our little princess veer so dangerously close to disaster.

Could Cinderella’s Glass Slippers Physically Exist Without Shattering?

In order for her to be safe enough, we would take a safety factor of at least 2, and also assume that the bending stress can go as high as 75 MPa. This means that her shoes need to be made of glass that has a yield strength of at least 150 MPa.

Safety glass (thermal toughened glass) seems to be a good bet. It has a yield strength of about 200 MPa and a higher Young’s Modulus too, so I imagine Cinderella can use it safely without fear of it breaking just when she is shaking a leg with our awesome prince. Ideally, we would also want it mixed with something to make it less brittle, but I don’t want to make it too different from glass or the answer becomes meaningless.

Steve Davis points out an interesting issue — what happens when she starts running out of the castle at midnight approaches?

When Cinderella runs, I expect the impact force to be 3-5 times that of the regular walking force (this is somewhat supported by the paper “Ground reaction forces at different speeds of human walking and running“). The shoes should be safe for these values.

We must also take into consideration the fact that Cinderella’s dress would probably not let her take long strides. This would mean that her stepping angle would remain within safe limits, further ensuring that her shoes don’t break.

Most importantly, she would be well-advised to develop a toe-first foot strike,which would totally solve the problem. This cannot be maintained for large distances, but would certainly take Cinderella out of the danger zone.

Bharat Jakati points out another caveat. What if the friction between her shoes and the ground/floor is so low that she slips? Well, we can assume that the flooring is either made of stone or is carpetted. The coefficient of friction for Glass on Stone is about 0.42, which is not very high, but is high enough for her to not slip. I couldn’t get a value for the coefficient for glass on carpet, but I imagine it to be similar.

And yes, I am well aware that Cinderella’s shoes were most likely made of fur and that the glass in the story is mostly a result of mistranslation. But what’s the fun in that?

Picture: Shutterstock/MR Shining

What qualities would the glass in Cinderella’s slippers need to have in order for her to walk and dance comfortably (and hold her weight)?originally appeared on Quora. You can follow Quora onTwitter, Facebook and Google+.

This answer has been lightly edited for grammar and clarity.


The Cheapest NBN 50 Plans

It’s the most popular NBN speed in Australia for a reason. Here are the cheapest plans available.

At Gizmodo, we independently select and write about stuff we love and think you'll like too. We have affiliate and advertising partnerships, which means we may collect a share of sales or other compensation from the links on this page. BTW – prices are accurate and items in stock at the time of posting.