The Batman Equation

I never had any idea maths could be so delightful. Can anyone replicate and verify this for me with a graphing calculator?

[Via Ryan North]

Discuss

(7 Comments)
  • [–]

    Sam

    Saturday, July 30, 2011 at 3:11 PM

    Just tried this in “Grapher” for Mac, and it didn’t seem to work, it may be too complex for it though.

  • [–]

    Steve

    Saturday, July 30, 2011 at 3:43 PM

    From attempting to copy out the equation, I got this in Microsoft Mathematics http://images.devs-on.net/Image/I7KMvSdXc4D3WOE-Screen1.png

  • [–]

    Jeremy

    Saturday, July 30, 2011 at 4:07 PM

    It actually works, except it seems to be missing the bits on the ends…Gizmodo check your inbox for proof.

  • [–]

    Brock Taffe

    Saturday, July 30, 2011 at 5:21 PM

    Yeah I couldn’t get it to work either.

  • [–]

    Stephen

    Saturday, July 30, 2011 at 7:06 PM

    Nerd alert!

  • [–]

    Sebastian Key

    Saturday, July 30, 2011 at 7:48 PM

    ((x/7)^2*sqrt(abs(abs(x)-3)/(abs(x)-3))+(y/3)^2*sqrt(abs(y+3*sqrt(33)/7)/(y+3*sqrt(33)/7))-1)*(abs(x/2)-(3*sqrt(33)-7)/112*x^2-3+sqrt(1-(abs(abs(x)-2)-1)^2)-y)*(9*sqrt(abs((abs(x)-1)*(abs(x)-0.75))/((1-abs(x))*(abs(x)-0.75)))-8*abs(x)-y)*(3*abs(x)+0.75*sqrt((abs((abs(x)-0.75)*(abs(x)-0.5))/((0.75-abs(x))*(abs(x)-0.5))))-y)*(2.25*sqrt(abs((x-0.5)*(x+0.5))/((0.5-x)*(0.5+x)))-y)*(6*sqrt(10)/7+(1.5-0.5*abs(x))*sqrt(abs(abs(x)-1)/(abs(x)-1))-6*sqrt(10)/14*sqrt(4-(abs(x)-1)^2)-y)=0

    Can someone verify this is right? I have tried an implicit plot and it wont plot. also try putting these x,y co-ordinates in and see that in fact approximately =0 and are point on the Graph. (4.8,2.18361242) and (-2.45,1.03524)

  • [–]

    RealtimeY

    Sunday, July 31, 2011 at 10:25 AM

    It does work. I entered it into TI N-Spire CAS Student Software, solved for y, which returned several functions and just copied those into Geogebra and it worked.

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